A lower bound on the maximum permanent in
&Lambdank
Let Pnk be the maximum value achieved by the
permanent over &Lambdank, the set of
(0,1)-matrices of order n with exactly k ones in each row and
column. Bregman proved that Pnk<=
k!n/k. It is shown here that Pnk>=
k!tr! where n=tk+r and 0<= r<k. From this simple bound we
derive that (Pnk)1/n is asymptotically
equal to k!1/k whenever k=o(n) and deduce a number of
structural results about matrices which achieve
Pnk. These include restrictions for large n
and k on the number of components which may be drawn from
&Lambdak+ck for a constant c>=1.
Our results can be directly applied to maximisation problems dealing
with the number of extensions to Latin rectangles or the number of
perfect matchings in regular bipartite graphs.
Last modified: Mon May 31 16:45:27 EST 2004